What are the solutions to the equation b^2-4/9 =0 ?

The solutions to the equation b^2-4/9 =0 are b= 2/3 ,b=-2/3

Find the zeros of b^2-4/9 =0

The zeros of b^2-4/9 =0 are b= 2/3 ,b=-2/3

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b^{2} - \frac{4}{9} = 0

b = \frac{2}{3}, b = - \frac{2}{3}

Decimal Notation

b = 0.66666 \dots, b = - 0.66666 \dots

Solution steps

b^{2} - \frac{4}{9} = 0

Move

\frac{4}{9}

to the right side

b^{2} = \frac{4}{9}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

b = \frac{4}{9}, b = - \frac{4}{9}

\frac{4}{9} = \frac{2}{3}

- \frac{4}{9} = - \frac{2}{3}

b = \frac{2}{3}, b = - \frac{2}{3}

9 w^{2} - 31 w - 20 = 0

2 (w^{2} - 2 w) = 5

4.9 t^{2} - 205.06 t - 210 = 0

3 y^{2} - 20 y + 9 = - y^{2} + 8 y - 40

5 u (u + 2) + 5 = 0

What are the solutions to the equation b^2-4/9 =0 ?
The solutions to the equation b^2-4/9 =0 are b= 2/3 ,b=-2/3
Find the zeros of b^2-4/9 =0
The zeros of b^2-4/9 =0 are b= 2/3 ,b=-2/3