What are the solutions to the equation 4x^2-4x-99=0 ?

The solutions to the equation 4x^2-4x-99=0 are x= 11/2 ,x=-9/2

Find the zeros of 4x^2-4x-99=0

The zeros of 4x^2-4x-99=0 are x= 11/2 ,x=-9/2

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4 x^{2} - 4 x - 99 = 0

x = \frac{11}{2}, x = - \frac{9}{2}

Decimal Notation

x = 5.5, x = - 4.5

Solution steps

4 x^{2} - 4 x - 99 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 4 ( - 99 )}{2 \cdot 4}

(- 4)^{2} - 4 \cdot 4 (- 99) = 40

x_{1, 2} = \frac{- ( - 4 ) \pm 40}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 40}{2 \cdot 4}, x_{2} = \frac{- ( - 4 ) - 40}{2 \cdot 4}

x = \frac{- ( - 4 ) + 40}{2 \cdot 4} : \frac{11}{2}

x = \frac{- ( - 4 ) - 40}{2 \cdot 4} : - \frac{9}{2}

The solutions to the quadratic equation are:

x = \frac{11}{2}, x = - \frac{9}{2}

(x - 5) (x - 5) = x (2 x - 6)

2 x - 2 x^{2} = 7

6 x^{2} - 3 x + 1 = 0

x, 5 (y + 1)^{3} + x^{2} = 1

3 x^{2} + 8 = 32

What are the solutions to the equation 4x^2-4x-99=0 ?
The solutions to the equation 4x^2-4x-99=0 are x= 11/2 ,x=-9/2
Find the zeros of 4x^2-4x-99=0
The zeros of 4x^2-4x-99=0 are x= 11/2 ,x=-9/2