What are the solutions to the equation 18x^2-25=-8x^2-(-16) ?

The solutions to the equation 18x^2-25=-8x^2-(-16) are x=sqrt(41/26),x=-sqrt(41/26)

Find the zeros of 18x^2-25=-8x^2-(-16)

The zeros of 18x^2-25=-8x^2-(-16) are x=sqrt(41/26),x=-sqrt(41/26)

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18 x^{2} - 25 = - 8 x^{2} - (- 16)

x = \frac{41}{26}, x = - \frac{41}{26}

Decimal Notation

x = 1.25575 \dots, x = - 1.25575 \dots

Solution steps

18 x^{2} - 25 = - 8 x^{2} - (- 16)

Refine

18 x^{2} - 25 = - 8 x^{2} + 16

Move

25

to the right side

18 x^{2} = - 8 x^{2} + 41

Move

8 x^{2}

to the left side

26 x^{2} = 41

Divide both sides by

26

x^{2} = \frac{41}{26}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{41}{26}, x = - \frac{41}{26}

(2 x - 9)^{2} - 7 = 2

3 a^{2} x^{2} = 24 b^{4} c^{8}

2 x^{2} - 8 x + 8 = 0

3 (x^{2} - 1) + 2 (x - 5) - 20 = 0

x = x^{2} + x - 3

What are the solutions to the equation 18x^2-25=-8x^2-(-16) ?
The solutions to the equation 18x^2-25=-8x^2-(-16) are x=sqrt(41/26),x=-sqrt(41/26)
Find the zeros of 18x^2-25=-8x^2-(-16)
The zeros of 18x^2-25=-8x^2-(-16) are x=sqrt(41/26),x=-sqrt(41/26)