What are the solutions to the equation x^2+100x-7500=0 ?

The solutions to the equation x^2+100x-7500=0 are x=50,x=-150

Find the zeros of x^2+100x-7500=0

The zeros of x^2+100x-7500=0 are x=50,x=-150

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x^{2} + 100 x - 7500 = 0

x = 50, x = - 150

Solution steps

x^{2} + 100 x - 7500 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 100 \pm 10 0 ^{2} - 4 \cdot 1 \cdot ( - 7500 )}{2 \cdot 1}

10 0^{2} - 4 \cdot 1 \cdot (- 7500) = 200

x_{1, 2} = \frac{- 100 \pm 200}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 100 + 200}{2 \cdot 1}, x_{2} = \frac{- 100 - 200}{2 \cdot 1}

x = \frac{- 100 + 200}{2 \cdot 1} : 50

x = \frac{- 100 - 200}{2 \cdot 1} : - 150

The solutions to the quadratic equation are:

x = 50, x = - 150

5 = 10 t + \frac{1}{2} (- 9.8) t^{2}

25 x - 19 = 3 (x^{2} + 3)

x^{2} + x - 12 = 0

(2 x - 5)^{2} = 169

x^{3} - 3 x - 2 = (x - a)^{2} (x + b)

What are the solutions to the equation x^2+100x-7500=0 ?
The solutions to the equation x^2+100x-7500=0 are x=50,x=-150
Find the zeros of x^2+100x-7500=0
The zeros of x^2+100x-7500=0 are x=50,x=-150