What are the solutions to the equation (x+3)(x-2)=4(x-2) ?

The solutions to the equation (x+3)(x-2)=4(x-2) are x=2,x=1

Find the zeros of (x+3)(x-2)=4(x-2)

The zeros of (x+3)(x-2)=4(x-2) are x=2,x=1

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(x + 3) (x - 2) = 4 (x - 2)

x = 2, x = 1

Solution steps

(x + 3) (x - 2) = 4 (x - 2)

Move

4 (x - 2)

to the left side

(x + 3) (x - 2) - 4 (x - 2) = 0

Factor

(x + 3) (x - 2) - 4 (x - 2) : (x - 2) (x - 1)

(x - 2) (x - 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 2 = 0 or x - 1 = 0

Solve

x - 2 = 0 : x = 2

Solve

x - 1 = 0 : x = 1

The solutions to the quadratic equation are:

x = 2, x = 1

(x + 9)^{2} = 24

11 = x^{2} + x - 1

5 x^{2} - 3 x = x^{2} - 4 x + 7

4 y^{2} + 12 y - 3 = 5 y

2 b^{2} - 32 = 0

What are the solutions to the equation (x+3)(x-2)=4(x-2) ?
The solutions to the equation (x+3)(x-2)=4(x-2) are x=2,x=1
Find the zeros of (x+3)(x-2)=4(x-2)
The zeros of (x+3)(x-2)=4(x-2) are x=2,x=1