What are the solutions to the equation q^2+2q-15=-3q ?

The solutions to the equation q^2+2q-15=-3q are q=(-5+sqrt(85))/2 ,q=(-5-sqrt(85))/2

Find the zeros of q^2+2q-15=-3q

The zeros of q^2+2q-15=-3q are q=(-5+sqrt(85))/2 ,q=(-5-sqrt(85))/2

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q^{2} + 2 q - 15 = - 3 q

q = \frac{- 5 + 85}{2}, q = \frac{- 5 - 85}{2}

Decimal Notation

q = 2.10977 \dots, q = - 7.10977 \dots

Solution steps

q^{2} + 2 q - 15 = - 3 q

Move

3 q

to the left side

q^{2} + 5 q - 15 = 0

Solve with the quadratic formula

q_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 1 \cdot ( - 15 )}{2 \cdot 1}

5^{2} - 4 \cdot 1 \cdot (- 15) = 85

q_{1, 2} = \frac{- 5 \pm 85}{2 \cdot 1}

Separate the solutions

q_{1} = \frac{- 5 + 85}{2 \cdot 1}, q_{2} = \frac{- 5 - 85}{2 \cdot 1}

q = \frac{- 5 + 85}{2 \cdot 1} : \frac{- 5 + 85}{2}

q = \frac{- 5 - 85}{2 \cdot 1} : \frac{- 5 - 85}{2}

The solutions to the quadratic equation are:

q = \frac{- 5 + 85}{2}, q = \frac{- 5 - 85}{2}

a \cdot (x^{2}) + b \cdot x = - c

5 t^{2} + 7 t - 1 = 0

y, y^{2} - x^{2} + 1 = 50

12 + y^{2} - 6 y = 0

2 x^{2} - x - 1 = 0

What are the solutions to the equation q^2+2q-15=-3q ?
The solutions to the equation q^2+2q-15=-3q are q=(-5+sqrt(85))/2 ,q=(-5-sqrt(85))/2
Find the zeros of q^2+2q-15=-3q
The zeros of q^2+2q-15=-3q are q=(-5+sqrt(85))/2 ,q=(-5-sqrt(85))/2