What are the solutions to the equation -6x^2+36x=-714 ?

The solutions to the equation -6x^2+36x=-714 are x=3-8sqrt(2),x=3+8sqrt(2)

Find the zeros of -6x^2+36x=-714

The zeros of -6x^2+36x=-714 are x=3-8sqrt(2),x=3+8sqrt(2)

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- 6 x^{2} + 36 x = - 714

x = 3 - 82, x = 3 + 82

Decimal Notation

x = - 8.31370 \dots, x = 14.31370 \dots

Solution steps

- 6 x^{2} + 36 x = - 714

Move

714

to the left side

- 6 x^{2} + 36 x + 714 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 36 \pm 3 6 ^{2} - 4 ( - 6 ) \cdot 714}{2 ( - 6 )}

3 6^{2} - 4 (- 6) \cdot 714 = 962

x_{1, 2} = \frac{- 36 \pm 96 2}{2 ( - 6 )}

Separate the solutions

x_{1} = \frac{- 36 + 96 2}{2 ( - 6 )}, x_{2} = \frac{- 36 - 96 2}{2 ( - 6 )}

x = \frac{- 36 + 96 2}{2 ( - 6 )} : 3 - 82

x = \frac{- 36 - 96 2}{2 ( - 6 )} : 3 + 82

The solutions to the quadratic equation are:

x = 3 - 82, x = 3 + 82

- 5 x^{2} + x - 3 = 0

x, 3 x^{2} - 6 x y = 0

x, x^{2} - 5 x + 6 = y

3 w (w - 2) = 10

x^{2} - 17 x - 18 = 0

What are the solutions to the equation -6x^2+36x=-714 ?
The solutions to the equation -6x^2+36x=-714 are x=3-8sqrt(2),x=3+8sqrt(2)
Find the zeros of -6x^2+36x=-714
The zeros of -6x^2+36x=-714 are x=3-8sqrt(2),x=3+8sqrt(2)