What are the solutions to the equation -8x^2-4x+24=0 ?

The solutions to the equation -8x^2-4x+24=0 are x=-2,x= 3/2

Find the zeros of -8x^2-4x+24=0

The zeros of -8x^2-4x+24=0 are x=-2,x= 3/2

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- 8 x^{2} - 4 x + 24 = 0

x = - 2, x = \frac{3}{2}

Decimal Notation

x = - 2, x = 1.5

Solution steps

- 8 x^{2} - 4 x + 24 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 ( - 8 ) \cdot 24}{2 ( - 8 )}

(- 4)^{2} - 4 (- 8) \cdot 24 = 28

x_{1, 2} = \frac{- ( - 4 ) \pm 28}{2 ( - 8 )}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 28}{2 ( - 8 )}, x_{2} = \frac{- ( - 4 ) - 28}{2 ( - 8 )}

x = \frac{- ( - 4 ) + 28}{2 ( - 8 )} : - 2

x = \frac{- ( - 4 ) - 28}{2 ( - 8 )} : \frac{3}{2}

The solutions to the quadratic equation are:

x = - 2, x = \frac{3}{2}

t, 300 = t^{2} + 2 t

0 = 5 t^{2} + 3 t - 2

n^{2} = n + 20

12 b^{2} - 20 b = 0

2 x^{2} - 8 x + 11

What are the solutions to the equation -8x^2-4x+24=0 ?
The solutions to the equation -8x^2-4x+24=0 are x=-2,x= 3/2
Find the zeros of -8x^2-4x+24=0
The zeros of -8x^2-4x+24=0 are x=-2,x= 3/2