What are the solutions to the equation 15-2x^2=3x ?

The solutions to the equation 15-2x^2=3x are x=-(3+sqrt(129))/4 ,x=(sqrt(129)-3)/4

Find the zeros of 15-2x^2=3x

The zeros of 15-2x^2=3x are x=-(3+sqrt(129))/4 ,x=(sqrt(129)-3)/4

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15 - 2 x^{2} = 3 x

x = - \frac{3 + 129}{4}, x = \frac{129 - 3}{4}

Decimal Notation

x = - 3.58945 \dots, x = 2.08945 \dots

Solution steps

15 - 2 x^{2} = 3 x

Move

3 x

to the left side

15 - 2 x^{2} - 3 x = 0

Write in the standard form

a x^{2} + b x + c = 0

- 2 x^{2} - 3 x + 15 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 ( - 2 ) \cdot 15}{2 ( - 2 )}

(- 3)^{2} - 4 (- 2) \cdot 15 = 129

x_{1, 2} = \frac{- ( - 3 ) \pm 129}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 129}{2 ( - 2 )}, x_{2} = \frac{- ( - 3 ) - 129}{2 ( - 2 )}

x = \frac{- ( - 3 ) + 129}{2 ( - 2 )} : - \frac{3 + 129}{4}

x = \frac{- ( - 3 ) - 129}{2 ( - 2 )} : \frac{129 - 3}{4}

The solutions to the quadratic equation are:

x = - \frac{3 + 129}{4}, x = \frac{129 - 3}{4}

4 x^{2} - 16 x + 144 = 0

x^{2} + 8 x + 19

(y + 2) (y - 3) = - 6

3 x - 4 = 5 x^{2}

x^{2} - 13 x = 48

What are the solutions to the equation 15-2x^2=3x ?
The solutions to the equation 15-2x^2=3x are x=-(3+sqrt(129))/4 ,x=(sqrt(129)-3)/4
Find the zeros of 15-2x^2=3x
The zeros of 15-2x^2=3x are x=-(3+sqrt(129))/4 ,x=(sqrt(129)-3)/4