What are the solutions to the equation 3x^2-41x=-60 ?

The solutions to the equation 3x^2-41x=-60 are x=12,x= 5/3

Find the zeros of 3x^2-41x=-60

The zeros of 3x^2-41x=-60 are x=12,x= 5/3

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3 x^{2} - 41 x = - 60

x = 12, x = \frac{5}{3}

Decimal Notation

x = 12, x = 1.66666 \dots

Solution steps

3 x^{2} - 41 x = - 60

Move

60

to the left side

3 x^{2} - 41 x + 60 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 41 ) \pm ( - 41 ) ^{2} - 4 \cdot 3 \cdot 60}{2 \cdot 3}

(- 41)^{2} - 4 \cdot 3 \cdot 60 = 31

x_{1, 2} = \frac{- ( - 41 ) \pm 31}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 41 ) + 31}{2 \cdot 3}, x_{2} = \frac{- ( - 41 ) - 31}{2 \cdot 3}

x = \frac{- ( - 41 ) + 31}{2 \cdot 3} : 12

x = \frac{- ( - 41 ) - 31}{2 \cdot 3} : \frac{5}{3}

The solutions to the quadratic equation are:

x = 12, x = \frac{5}{3}

x, h x^{2} + 9 h^{2} x = 3 + x

3 x^{2} - 64 = 0

h^{2} + 3 h = 30

2 (x - 6)^{2} + 10 = 20

5 = x^{2} - 4 x

What are the solutions to the equation 3x^2-41x=-60 ?
The solutions to the equation 3x^2-41x=-60 are x=12,x= 5/3
Find the zeros of 3x^2-41x=-60
The zeros of 3x^2-41x=-60 are x=12,x= 5/3