What are the solutions to the equation 8y^2-24y=0 ?

The solutions to the equation 8y^2-24y=0 are y=3,y=0

Find the zeros of 8y^2-24y=0

The zeros of 8y^2-24y=0 are y=3,y=0

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8 y^{2} - 24 y = 0

y = 3, y = 0

Solution steps

8 y^{2} - 24 y = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 24 ) \pm ( - 24 ) ^{2} - 4 \cdot 8 \cdot 0}{2 \cdot 8}

(- 24)^{2} - 4 \cdot 8 \cdot 0 = 24

y_{1, 2} = \frac{- ( - 24 ) \pm 24}{2 \cdot 8}

Separate the solutions

y_{1} = \frac{- ( - 24 ) + 24}{2 \cdot 8}, y_{2} = \frac{- ( - 24 ) - 24}{2 \cdot 8}

y = \frac{- ( - 24 ) + 24}{2 \cdot 8} : 3

y = \frac{- ( - 24 ) - 24}{2 \cdot 8} : 0

The solutions to the quadratic equation are:

y = 3, y = 0

x, f (x + 2) = x^{2} - 2 x + 5

y, x = y^{2} + 2 y - 1

x^{2} - 2 x + 6 = 2 x + 11

x^{2} = 8 x - 15

x^{2} - 6 x - 71 = 0

What are the solutions to the equation 8y^2-24y=0 ?
The solutions to the equation 8y^2-24y=0 are y=3,y=0
Find the zeros of 8y^2-24y=0
The zeros of 8y^2-24y=0 are y=3,y=0