What are the solutions to the equation x^2+x-110=0 ?

The solutions to the equation x^2+x-110=0 are x=10,x=-11

Find the zeros of x^2+x-110=0

The zeros of x^2+x-110=0 are x=10,x=-11

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x^{2} + x - 110 = 0

x = 10, x = - 11

Solution steps

x^{2} + x - 110 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot ( - 110 )}{2 \cdot 1}

1^{2} - 4 \cdot 1 \cdot (- 110) = 21

x_{1, 2} = \frac{- 1 \pm 21}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 1 + 21}{2 \cdot 1}, x_{2} = \frac{- 1 - 21}{2 \cdot 1}

x = \frac{- 1 + 21}{2 \cdot 1} : 10

x = \frac{- 1 - 21}{2 \cdot 1} : - 11

The solutions to the quadratic equation are:

x = 10, x = - 11

x^{2} + 55 = - 14 x + 10

0.3 (n - 5) = 0.4 - 0.2 n

2 x^{2} + 6 x - 20

- 3 x^{2} - 54 x - 240 = 0

\frac{500000}{x ^{2} + 400} < 340

What are the solutions to the equation x^2+x-110=0 ?
The solutions to the equation x^2+x-110=0 are x=10,x=-11
Find the zeros of x^2+x-110=0
The zeros of x^2+x-110=0 are x=10,x=-11