What are the solutions to the equation 4c^2+17c+12=0 ?

The solutions to the equation 4c^2+17c+12=0 are c=(-17+sqrt(97))/8 ,c=(-17-sqrt(97))/8

Find the zeros of 4c^2+17c+12=0

The zeros of 4c^2+17c+12=0 are c=(-17+sqrt(97))/8 ,c=(-17-sqrt(97))/8

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4 c^{2} + 17 c + 12 = 0

c = \frac{- 17 + 97}{8}, c = \frac{- 17 - 97}{8}

Decimal Notation

c = - 0.89389 \dots, c = - 3.35610 \dots

Solution steps

4 c^{2} + 17 c + 12 = 0

Solve with the quadratic formula

c_{1, 2} = \frac{- 17 \pm 1 7 ^{2} - 4 \cdot 4 \cdot 12}{2 \cdot 4}

1 7^{2} - 4 \cdot 4 \cdot 12 = 97

c_{1, 2} = \frac{- 17 \pm 97}{2 \cdot 4}

Separate the solutions

c_{1} = \frac{- 17 + 97}{2 \cdot 4}, c_{2} = \frac{- 17 - 97}{2 \cdot 4}

c = \frac{- 17 + 97}{2 \cdot 4} : \frac{- 17 + 97}{8}

c = \frac{- 17 - 97}{2 \cdot 4} : \frac{- 17 - 97}{8}

The solutions to the quadratic equation are:

c = \frac{- 17 + 97}{8}, c = \frac{- 17 - 97}{8}

- 3 x^{2} - 3 x + 36 = 0

x^{2} + 3 x = 6 x

x^{2} - 22 x - 3 = 0

3 x - 5 x (x - 1) = 3

5 x^{2} = 30 x - 45

What are the solutions to the equation 4c^2+17c+12=0 ?
The solutions to the equation 4c^2+17c+12=0 are c=(-17+sqrt(97))/8 ,c=(-17-sqrt(97))/8
Find the zeros of 4c^2+17c+12=0
The zeros of 4c^2+17c+12=0 are c=(-17+sqrt(97))/8 ,c=(-17-sqrt(97))/8