What are the solutions to the equation completesquare y^2+3y-1 ?

The solutions to the equation completesquare y^2+3y-1 are (y+3/2)^2-13/4

Find the zeros of completesquare y^2+3y-1

The zeros of completesquare y^2+3y-1 are (y+3/2)^2-13/4

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complete the square

y^{2} + 3 y - 1

(y + \frac{3}{2})^{2} - \frac{13}{4}

Solution steps

y^{2} + 3 y - 1

Write

y^{2} + 3 y - 1

in the form:

x^{2} + 2 a x + a^{2}

2 a = 3 : a = \frac{3}{2}

Add and subtract

(\frac{3}{2})^{2}

y^{2} + 3 y - 1 + (\frac{3}{2})^{2} - (\frac{3}{2})^{2}

x^{2} + 2 a x + a^{2} = (x + a)^{2}

y^{2} + 3 y + (\frac{3}{2})^{2} = (y + \frac{3}{2})^{2}

(y + \frac{3}{2})^{2} - 1 - (\frac{3}{2})^{2}

Simplify

(y + \frac{3}{2})^{2} - \frac{13}{4}

(x - 1)^{2} - x (2 x - 5) = 0

x^{2} - 15 x - 16 = - 9 x - 9

36 x^{2} + 4 = 40

3 x^{2} + 8 = 13

x, f (x + 3) = x^{2} - 4 x + 4

What are the solutions to the equation completesquare y^2+3y-1 ?
The solutions to the equation completesquare y^2+3y-1 are (y+3/2)^2-13/4
Find the zeros of completesquare y^2+3y-1
The zeros of completesquare y^2+3y-1 are (y+3/2)^2-13/4