What are the solutions to the equation 3x^2+5x=7(x^2+x) ?

The solutions to the equation 3x^2+5x=7(x^2+x) are x=-1/2 ,x=0

Find the zeros of 3x^2+5x=7(x^2+x)

The zeros of 3x^2+5x=7(x^2+x) are x=-1/2 ,x=0

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3 x^{2} + 5 x = 7 (x^{2} + x)

x = - \frac{1}{2}, x = 0

Decimal Notation

x = - 0.5, x = 0

Solution steps

3 x^{2} + 5 x = 7 (x^{2} + x)

Expand

7 (x^{2} + x) : 7 x^{2} + 7 x

3 x^{2} + 5 x = 7 x^{2} + 7 x

Move

7 x

to the left side

3 x^{2} - 2 x = 7 x^{2}

Move

7 x^{2}

to the left side

- 4 x^{2} - 2 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 ( - 4 ) \cdot 0}{2 ( - 4 )}

(- 2)^{2} - 4 (- 4) \cdot 0 = 2

x_{1, 2} = \frac{- ( - 2 ) \pm 2}{2 ( - 4 )}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2}{2 ( - 4 )}, x_{2} = \frac{- ( - 2 ) - 2}{2 ( - 4 )}

x = \frac{- ( - 2 ) + 2}{2 ( - 4 )} : - \frac{1}{2}

x = \frac{- ( - 2 ) - 2}{2 ( - 4 )} : 0

The solutions to the quadratic equation are:

x = - \frac{1}{2}, x = 0

5 x^{2} + 40 x - 410 = 0

y, y^{2} - y - x^{2} = 0

2 (x - 1)^{2} - (x + 4) (x - 4) = 19 - x

2 x^{2} - 3 x - 10

2 x^{2} - 12 x + 16 = 10

What are the solutions to the equation 3x^2+5x=7(x^2+x) ?
The solutions to the equation 3x^2+5x=7(x^2+x) are x=-1/2 ,x=0
Find the zeros of 3x^2+5x=7(x^2+x)
The zeros of 3x^2+5x=7(x^2+x) are x=-1/2 ,x=0