What are the solutions to the equation 5q^2-7q+4=6 ?

The solutions to the equation 5q^2-7q+4=6 are q=(7+sqrt(89))/(10),q=(7-sqrt(89))/(10)

Find the zeros of 5q^2-7q+4=6

The zeros of 5q^2-7q+4=6 are q=(7+sqrt(89))/(10),q=(7-sqrt(89))/(10)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

5 q^{2} - 7 q + 4 = 6

q = \frac{7 + 89}{10}, q = \frac{7 - 89}{10}

Decimal Notation

q = 1.64339 \dots, q = - 0.24339 \dots

Solution steps

5 q^{2} - 7 q + 4 = 6

Move

6

to the left side

5 q^{2} - 7 q - 2 = 0

Solve with the quadratic formula

q_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 5 ( - 2 )}{2 \cdot 5}

(- 7)^{2} - 4 \cdot 5 (- 2) = 89

q_{1, 2} = \frac{- ( - 7 ) \pm 89}{2 \cdot 5}

Separate the solutions

q_{1} = \frac{- ( - 7 ) + 89}{2 \cdot 5}, q_{2} = \frac{- ( - 7 ) - 89}{2 \cdot 5}

q = \frac{- ( - 7 ) + 89}{2 \cdot 5} : \frac{7 + 89}{10}

q = \frac{- ( - 7 ) - 89}{2 \cdot 5} : \frac{7 - 89}{10}

The solutions to the quadratic equation are:

q = \frac{7 + 89}{10}, q = \frac{7 - 89}{10}

x, k = \frac{1}{2} k x^{2}

5 x^{2} - 600 x + 18000 = 0

(3 x + 3) (x + 2) = 5

(2 x + 1)^{2} - (2 x + 1) (x - 3) = 0

x, x^{2} - 7 x + 6 = 0

What are the solutions to the equation 5q^2-7q+4=6 ?
The solutions to the equation 5q^2-7q+4=6 are q=(7+sqrt(89))/(10),q=(7-sqrt(89))/(10)
Find the zeros of 5q^2-7q+4=6
The zeros of 5q^2-7q+4=6 are q=(7+sqrt(89))/(10),q=(7-sqrt(89))/(10)