What are the solutions to the equation 7x^2+18x=10x^2+12x ?

The solutions to the equation 7x^2+18x=10x^2+12x are x=0,x=2

Find the zeros of 7x^2+18x=10x^2+12x

The zeros of 7x^2+18x=10x^2+12x are x=0,x=2

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7 x^{2} + 18 x = 10 x^{2} + 12 x

x = 0, x = 2

Solution steps

7 x^{2} + 18 x = 10 x^{2} + 12 x

Move

12 x

to the left side

7 x^{2} + 6 x = 10 x^{2}

Move

10 x^{2}

to the left side

- 3 x^{2} + 6 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 ( - 3 ) \cdot 0}{2 ( - 3 )}

6^{2} - 4 (- 3) \cdot 0 = 6

x_{1, 2} = \frac{- 6 \pm 6}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- 6 + 6}{2 ( - 3 )}, x_{2} = \frac{- 6 - 6}{2 ( - 3 )}

x = \frac{- 6 + 6}{2 ( - 3 )} : 0

x = \frac{- 6 - 6}{2 ( - 3 )} : 2

The solutions to the quadratic equation are:

x = 0, x = 2

- 25 x^{2} - 30 x - 9 = 0

\frac{q ( q + 7 )}{7} - q = 4 - q^{2}

3 y^{2} + 9 y + 15

a x^{2} - (a + 2) x - 1 = 0

x, x^{2} y + x - y + 1 = 0

What are the solutions to the equation 7x^2+18x=10x^2+12x ?
The solutions to the equation 7x^2+18x=10x^2+12x are x=0,x=2
Find the zeros of 7x^2+18x=10x^2+12x
The zeros of 7x^2+18x=10x^2+12x are x=0,x=2