What are the solutions to the equation 4x^2-6x+5=x+1 ?

The solutions to the equation 4x^2-6x+5=x+1 are x= 7/8+i(sqrt(15))/8 ,x= 7/8-i(sqrt(15))/8

Find the zeros of 4x^2-6x+5=x+1

The zeros of 4x^2-6x+5=x+1 are x= 7/8+i(sqrt(15))/8 ,x= 7/8-i(sqrt(15))/8

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4 x^{2} - 6 x + 5 = x + 1

x = \frac{7}{8} + i \frac{15}{8}, x = \frac{7}{8} - i \frac{15}{8}

Solution steps

4 x^{2} - 6 x + 5 = x + 1

Move

1

to the left side

4 x^{2} - 6 x + 4 = x

Move

x

to the left side

4 x^{2} - 7 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 4 \cdot 4}{2 \cdot 4}

Simplify

(- 7)^{2} - 4 \cdot 4 \cdot 4 : 15 i

x_{1, 2} = \frac{- ( - 7 ) \pm 15 i}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 7 ) + 15 i}{2 \cdot 4}, x_{2} = \frac{- ( - 7 ) - 15 i}{2 \cdot 4}

x = \frac{- ( - 7 ) + 15 i}{2 \cdot 4} : \frac{7}{8} + i \frac{15}{8}

x = \frac{- ( - 7 ) - 15 i}{2 \cdot 4} : \frac{7}{8} - i \frac{15}{8}

The solutions to the quadratic equation are:

x = \frac{7}{8} + i \frac{15}{8}, x = \frac{7}{8} - i \frac{15}{8}

2 x^{2} + 18 = 90

x^{2} + 3 x - 21 = 0

2 x^{2} + 5 x - 63 = 0

x^{2} - 4 x - 21 = - 12

2 x^{2} + 8 x - 25 = 0

What are the solutions to the equation 4x^2-6x+5=x+1 ?
The solutions to the equation 4x^2-6x+5=x+1 are x= 7/8+i(sqrt(15))/8 ,x= 7/8-i(sqrt(15))/8
Find the zeros of 4x^2-6x+5=x+1
The zeros of 4x^2-6x+5=x+1 are x= 7/8+i(sqrt(15))/8 ,x= 7/8-i(sqrt(15))/8