What are the solutions to the equation -0.5x^2+3.2x+22=24 ?

The solutions to the equation -0.5x^2+3.2x+22=24 are x=(2(8-sqrt(39)))/5 ,x=(2(8+sqrt(39)))/5

Find the zeros of -0.5x^2+3.2x+22=24

The zeros of -0.5x^2+3.2x+22=24 are x=(2(8-sqrt(39)))/5 ,x=(2(8+sqrt(39)))/5

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- 0.5 x^{2} + 3.2 x + 22 = 24

x = \frac{2 ( 8 - 39 )}{5}, x = \frac{2 ( 8 + 39 )}{5}

Decimal Notation

x = 0.70200 \dots, x = 5.69799 \dots

Solution steps

- 0.5 x^{2} + 3.2 x + 22 = 24

Multiply both sides by

10

- 5 x^{2} + 32 x + 220 = 240

Move

240

to the left side

- 5 x^{2} + 32 x - 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 32 \pm 3 2 ^{2} - 4 ( - 5 ) ( - 20 )}{2 ( - 5 )}

3 2^{2} - 4 (- 5) (- 20) = 439

x_{1, 2} = \frac{- 32 \pm 4 39}{2 ( - 5 )}

Separate the solutions

x_{1} = \frac{- 32 + 4 39}{2 ( - 5 )}, x_{2} = \frac{- 32 - 4 39}{2 ( - 5 )}

x = \frac{- 32 + 4 39}{2 ( - 5 )} : \frac{2 ( 8 - 39 )}{5}

x = \frac{- 32 - 4 39}{2 ( - 5 )} : \frac{2 ( 8 + 39 )}{5}

The solutions to the quadratic equation are:

x = \frac{2 ( 8 - 39 )}{5}, x = \frac{2 ( 8 + 39 )}{5}

x - 2 x^{2}

39 x^{2} = 91

2 x^{2} + 5 x - 7 = 0

y, y^{2} = x^{3} - 8 x

4 x (x - 4) = 1

What are the solutions to the equation -0.5x^2+3.2x+22=24 ?
The solutions to the equation -0.5x^2+3.2x+22=24 are x=(2(8-sqrt(39)))/5 ,x=(2(8+sqrt(39)))/5
Find the zeros of -0.5x^2+3.2x+22=24
The zeros of -0.5x^2+3.2x+22=24 are x=(2(8-sqrt(39)))/5 ,x=(2(8+sqrt(39)))/5