What are the solutions to the equation 12x^2-7x=0 ?

The solutions to the equation 12x^2-7x=0 are x= 7/12 ,x=0

Find the zeros of 12x^2-7x=0

The zeros of 12x^2-7x=0 are x= 7/12 ,x=0

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12 x^{2} - 7 x = 0

x = \frac{7}{12}, x = 0

Solution steps

12 x^{2} - 7 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 12 \cdot 0}{2 \cdot 12}

(- 7)^{2} - 4 \cdot 12 \cdot 0 = 7

x_{1, 2} = \frac{- ( - 7 ) \pm 7}{2 \cdot 12}

Separate the solutions

x_{1} = \frac{- ( - 7 ) + 7}{2 \cdot 12}, x_{2} = \frac{- ( - 7 ) - 7}{2 \cdot 12}

x = \frac{- ( - 7 ) + 7}{2 \cdot 12} : \frac{7}{12}

x = \frac{- ( - 7 ) - 7}{2 \cdot 12} : 0

The solutions to the quadratic equation are:

x = \frac{7}{12}, x = 0

\frac{5}{- 10}

38 = - 16 t^{2} + 80 t + 102

- 9 \leq x + 5 \leq 15

16 c^{2} + 56 c + 49

(x + 4)^{2} + 5 (x + 4)

What are the solutions to the equation 12x^2-7x=0 ?
The solutions to the equation 12x^2-7x=0 are x= 7/12 ,x=0
Find the zeros of 12x^2-7x=0
The zeros of 12x^2-7x=0 are x= 7/12 ,x=0