What are the solutions to the equation x(x-7)-2=0 ?

The solutions to the equation x(x-7)-2=0 are x=(7+sqrt(57))/2 ,x=(7-sqrt(57))/2

Find the zeros of x(x-7)-2=0

The zeros of x(x-7)-2=0 are x=(7+sqrt(57))/2 ,x=(7-sqrt(57))/2

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x (x - 7) - 2 = 0

x = \frac{7 + 57}{2}, x = \frac{7 - 57}{2}

Decimal Notation

x = 7.27491 \dots, x = - 0.27491 \dots

Solution steps

x (x - 7) - 2 = 0

Expand

x (x - 7) - 2 : x^{2} - 7 x - 2

x^{2} - 7 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 1 \cdot ( - 2 )}{2 \cdot 1}

(- 7)^{2} - 4 \cdot 1 \cdot (- 2) = 57

x_{1, 2} = \frac{- ( - 7 ) \pm 57}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 7 ) + 57}{2 \cdot 1}, x_{2} = \frac{- ( - 7 ) - 57}{2 \cdot 1}

x = \frac{- ( - 7 ) + 57}{2 \cdot 1} : \frac{7 + 57}{2}

x = \frac{- ( - 7 ) - 57}{2 \cdot 1} : \frac{7 - 57}{2}

The solutions to the quadratic equation are:

x = \frac{7 + 57}{2}, x = \frac{7 - 57}{2}

x, x^{2} z + 3 y^{2} - x y = 10

2 x^{2} - 8 x - 1 = 0

4 r^{2} - 19 r + 21 = 2

x^{2} + 26 x - 15 = 0

- 3 x^{2} + 5 x - 15 = - 4 x^{2}

What are the solutions to the equation x(x-7)-2=0 ?
The solutions to the equation x(x-7)-2=0 are x=(7+sqrt(57))/2 ,x=(7-sqrt(57))/2
Find the zeros of x(x-7)-2=0
The zeros of x(x-7)-2=0 are x=(7+sqrt(57))/2 ,x=(7-sqrt(57))/2