What are the solutions to the equation x^2-14x+54=0 ?

The solutions to the equation x^2-14x+54=0 are x=7+sqrt(5)i,x=7-sqrt(5)i

Find the zeros of x^2-14x+54=0

The zeros of x^2-14x+54=0 are x=7+sqrt(5)i,x=7-sqrt(5)i

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x^{2} - 14 x + 54 = 0

x = 7 + 5 i, x = 7 - 5 i

Solution steps

x^{2} - 14 x + 54 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 14 ) \pm ( - 14 ) ^{2} - 4 \cdot 1 \cdot 54}{2 \cdot 1}

Simplify

(- 14)^{2} - 4 \cdot 1 \cdot 54 : 25 i

x_{1, 2} = \frac{- ( - 14 ) \pm 2 5 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 14 ) + 2 5 i}{2 \cdot 1}, x_{2} = \frac{- ( - 14 ) - 2 5 i}{2 \cdot 1}

x = \frac{- ( - 14 ) + 2 5 i}{2 \cdot 1} : 7 + 5 i

x = \frac{- ( - 14 ) - 2 5 i}{2 \cdot 1} : 7 - 5 i

The solutions to the quadratic equation are:

x = 7 + 5 i, x = 7 - 5 i

10 m = 7 m^{2}

2 y^{2} - 5 y = 12

x^{2} + 13 x - 114 = 0

20.76672 = x^{2} \cdot 12.7

x^{2} - 5 x = x - x^{2}

What are the solutions to the equation x^2-14x+54=0 ?
The solutions to the equation x^2-14x+54=0 are x=7+sqrt(5)i,x=7-sqrt(5)i
Find the zeros of x^2-14x+54=0
The zeros of x^2-14x+54=0 are x=7+sqrt(5)i,x=7-sqrt(5)i