What are the solutions to the equation 3m^2-2m-27=0 ?

The solutions to the equation 3m^2-2m-27=0 are m=(1+sqrt(82))/3 ,m=(1-sqrt(82))/3

Find the zeros of 3m^2-2m-27=0

The zeros of 3m^2-2m-27=0 are m=(1+sqrt(82))/3 ,m=(1-sqrt(82))/3

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3 m^{2} - 2 m - 27 = 0

m = \frac{1 + 82}{3}, m = \frac{1 - 82}{3}

Decimal Notation

m = 3.35179 \dots, m = - 2.68512 \dots

Solution steps

3 m^{2} - 2 m - 27 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 3 ( - 27 )}{2 \cdot 3}

(- 2)^{2} - 4 \cdot 3 (- 27) = 282

m_{1, 2} = \frac{- ( - 2 ) \pm 2 82}{2 \cdot 3}

Separate the solutions

m_{1} = \frac{- ( - 2 ) + 2 82}{2 \cdot 3}, m_{2} = \frac{- ( - 2 ) - 2 82}{2 \cdot 3}

m = \frac{- ( - 2 ) + 2 82}{2 \cdot 3} : \frac{1 + 82}{3}

m = \frac{- ( - 2 ) - 2 82}{2 \cdot 3} : \frac{1 - 82}{3}

The solutions to the quadratic equation are:

m = \frac{1 + 82}{3}, m = \frac{1 - 82}{3}

- 5 x^{2} - 12 x = 0

- 9 t + 10 t^{2} = 6

25 x^{2} - 14 x = 0

4 x^{2} - 19 x = 30

62 = \frac{1}{2} (h - 3) h

What are the solutions to the equation 3m^2-2m-27=0 ?
The solutions to the equation 3m^2-2m-27=0 are m=(1+sqrt(82))/3 ,m=(1-sqrt(82))/3
Find the zeros of 3m^2-2m-27=0
The zeros of 3m^2-2m-27=0 are m=(1+sqrt(82))/3 ,m=(1-sqrt(82))/3