What are the solutions to the equation m(m-7)=-10 ?

The solutions to the equation m(m-7)=-10 are m=5,m=2

Find the zeros of m(m-7)=-10

The zeros of m(m-7)=-10 are m=5,m=2

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m (m - 7) = - 10

m = 5, m = 2

Solution steps

m (m - 7) = - 10

Expand

m (m - 7) : m^{2} - 7 m

m^{2} - 7 m = - 10

Move

10

to the left side

m^{2} - 7 m + 10 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 1 \cdot 10}{2 \cdot 1}

(- 7)^{2} - 4 \cdot 1 \cdot 10 = 3

m_{1, 2} = \frac{- ( - 7 ) \pm 3}{2 \cdot 1}

Separate the solutions

m_{1} = \frac{- ( - 7 ) + 3}{2 \cdot 1}, m_{2} = \frac{- ( - 7 ) - 3}{2 \cdot 1}

m = \frac{- ( - 7 ) + 3}{2 \cdot 1} : 5

m = \frac{- ( - 7 ) - 3}{2 \cdot 1} : 2

The solutions to the quadratic equation are:

m = 5, m = 2

(2 y - 3)^{2} = 49

- 90 = x (x - 18)

4 x^{2} - 6 = 394

- 9 x^{2} - 15 x - 59 = 0

y, x = y^{2} + 1

What are the solutions to the equation m(m-7)=-10 ?
The solutions to the equation m(m-7)=-10 are m=5,m=2
Find the zeros of m(m-7)=-10
The zeros of m(m-7)=-10 are m=5,m=2