What are the solutions to the equation y^2-3y-2=0 ?

The solutions to the equation y^2-3y-2=0 are y=(3+sqrt(17))/2 ,y=(3-sqrt(17))/2

Find the zeros of y^2-3y-2=0

The zeros of y^2-3y-2=0 are y=(3+sqrt(17))/2 ,y=(3-sqrt(17))/2

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y^{2} - 3 y - 2 = 0

y = \frac{3 + 17}{2}, y = \frac{3 - 17}{2}

Decimal Notation

y = 3.56155 \dots, y = - 0.56155 \dots

Solution steps

y^{2} - 3 y - 2 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 1 \cdot ( - 2 )}{2 \cdot 1}

(- 3)^{2} - 4 \cdot 1 \cdot (- 2) = 17

y_{1, 2} = \frac{- ( - 3 ) \pm 17}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- ( - 3 ) + 17}{2 \cdot 1}, y_{2} = \frac{- ( - 3 ) - 17}{2 \cdot 1}

y = \frac{- ( - 3 ) + 17}{2 \cdot 1} : \frac{3 + 17}{2}

y = \frac{- ( - 3 ) - 17}{2 \cdot 1} : \frac{3 - 17}{2}

The solutions to the quadratic equation are:

y = \frac{3 + 17}{2}, y = \frac{3 - 17}{2}

x, p^{1} y = - x^{2} + 5 x - 4

\frac{9}{2} b^{2} = 32

h, rs + h^{2} = 1

(f - 8) (2 f + 9) = 0

v^{2} - 16 v - 32 = 0

What are the solutions to the equation y^2-3y-2=0 ?
The solutions to the equation y^2-3y-2=0 are y=(3+sqrt(17))/2 ,y=(3-sqrt(17))/2
Find the zeros of y^2-3y-2=0
The zeros of y^2-3y-2=0 are y=(3+sqrt(17))/2 ,y=(3-sqrt(17))/2