What are the solutions to the equation -7x^2-4=325 ?

The solutions to the equation -7x^2-4=325 are x=sqrt(47)i,x=-sqrt(47)i

Find the zeros of -7x^2-4=325

The zeros of -7x^2-4=325 are x=sqrt(47)i,x=-sqrt(47)i

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

- 7 x^{2} - 4 = 325

x = 47 i, x = - 47 i

Solution steps

- 7 x^{2} - 4 = 325

Move

4

to the right side

- 7 x^{2} = 329

Divide both sides by

- 7

x^{2} = - 47

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 47, x = - - 47

- 47 = 47 i

- - 47 = - 47 i

x = 47 i, x = - 47 i

x (x + 3) - 10 = 0

(- 4 - m)^{2} - 4 = 0

6 x^{2} + 3 x - 14 = 0

3 x^{2} - 6 x + 11

7 - x^{2} = x

What are the solutions to the equation -7x^2-4=325 ?
The solutions to the equation -7x^2-4=325 are x=sqrt(47)i,x=-sqrt(47)i
Find the zeros of -7x^2-4=325
The zeros of -7x^2-4=325 are x=sqrt(47)i,x=-sqrt(47)i