What are the solutions to the equation 8+2x^2=0 ?

The solutions to the equation 8+2x^2=0 are x=2i,x=-2i

Find the zeros of 8+2x^2=0

The zeros of 8+2x^2=0 are x=2i,x=-2i

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8 + 2 x^{2} = 0

x = 2 i, x = - 2 i

Solution steps

8 + 2 x^{2} = 0

Move

8

to the right side

2 x^{2} = - 8

Divide both sides by

2

x^{2} = - 4

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 4, x = - - 4

- 4 = 2 i

- - 4 = - 2 i

x = 2 i, x = - 2 i

x^{2} - 300 x + 12500 = 0

x^{2} - x = 8

t^{2} + 2 t - 19 = 5

2 x^{2} - 4 x + 15

u^{2} - 3 u - 10 = 0

What are the solutions to the equation 8+2x^2=0 ?
The solutions to the equation 8+2x^2=0 are x=2i,x=-2i
Find the zeros of 8+2x^2=0
The zeros of 8+2x^2=0 are x=2i,x=-2i