What are the solutions to the equation 3x-4x^2=-5 ?

The solutions to the equation 3x-4x^2=-5 are x=-(-3+sqrt(89))/8 ,x=(3+sqrt(89))/8

Find the zeros of 3x-4x^2=-5

The zeros of 3x-4x^2=-5 are x=-(-3+sqrt(89))/8 ,x=(3+sqrt(89))/8

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3 x - 4 x^{2} = - 5

x = - \frac{- 3 + 89}{8}, x = \frac{3 + 89}{8}

Decimal Notation

x = - 0.80424 \dots, x = 1.55424 \dots

Solution steps

3 x - 4 x^{2} = - 5

Move

5

to the left side

3 x - 4 x^{2} + 5 = 0

Write in the standard form

a x^{2} + b x + c = 0

- 4 x^{2} + 3 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 ( - 4 ) \cdot 5}{2 ( - 4 )}

3^{2} - 4 (- 4) \cdot 5 = 89

x_{1, 2} = \frac{- 3 \pm 89}{2 ( - 4 )}

Separate the solutions

x_{1} = \frac{- 3 + 89}{2 ( - 4 )}, x_{2} = \frac{- 3 - 89}{2 ( - 4 )}

x = \frac{- 3 + 89}{2 ( - 4 )} : - \frac{- 3 + 89}{8}

x = \frac{- 3 - 89}{2 ( - 4 )} : \frac{3 + 89}{8}

The solutions to the quadratic equation are:

x = - \frac{- 3 + 89}{8}, x = \frac{3 + 89}{8}

2 x (x - 3) + 7 = 0

2 x^{2} + 4 x + 16 = 0

3 d^{2} + 8 d = 40

2 a - a^{2} = 3

r^{2} + 9 r + 65 = - r

What are the solutions to the equation 3x-4x^2=-5 ?
The solutions to the equation 3x-4x^2=-5 are x=-(-3+sqrt(89))/8 ,x=(3+sqrt(89))/8
Find the zeros of 3x-4x^2=-5
The zeros of 3x-4x^2=-5 are x=-(-3+sqrt(89))/8 ,x=(3+sqrt(89))/8