What are the solutions to the equation 6x^2+3x-7=0 ?

The solutions to the equation 6x^2+3x-7=0 are x=(-3+sqrt(177))/(12),x=(-3-sqrt(177))/(12)

Find the zeros of 6x^2+3x-7=0

The zeros of 6x^2+3x-7=0 are x=(-3+sqrt(177))/(12),x=(-3-sqrt(177))/(12)

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6 x^{2} + 3 x - 7 = 0

x = \frac{- 3 + 177}{12}, x = \frac{- 3 - 177}{12}

Decimal Notation

x = 0.85867 \dots, x = - 1.35867 \dots

Solution steps

6 x^{2} + 3 x - 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 6 ( - 7 )}{2 \cdot 6}

3^{2} - 4 \cdot 6 (- 7) = 177

x_{1, 2} = \frac{- 3 \pm 177}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- 3 + 177}{2 \cdot 6}, x_{2} = \frac{- 3 - 177}{2 \cdot 6}

x = \frac{- 3 + 177}{2 \cdot 6} : \frac{- 3 + 177}{12}

x = \frac{- 3 - 177}{2 \cdot 6} : \frac{- 3 - 177}{12}

The solutions to the quadratic equation are:

x = \frac{- 3 + 177}{12}, x = \frac{- 3 - 177}{12}

2 x^{2} + 9 x = 10

(2 x + 1)^{2} = 121

0 = 2 x^{2} - 4

3 x^{2} + 25 - 7 x = 2 x^{2} + 15

x (5 x - 6) = - 1

What are the solutions to the equation 6x^2+3x-7=0 ?
The solutions to the equation 6x^2+3x-7=0 are x=(-3+sqrt(177))/(12),x=(-3-sqrt(177))/(12)
Find the zeros of 6x^2+3x-7=0
The zeros of 6x^2+3x-7=0 are x=(-3+sqrt(177))/(12),x=(-3-sqrt(177))/(12)