What are the solutions to the equation d^2=(+4-1)^2+(+16-1)^2 ?

The solutions to the equation d^2=(+4-1)^2+(+16-1)^2 are d=3sqrt(26),d=-3sqrt(26)

Find the zeros of d^2=(+4-1)^2+(+16-1)^2

The zeros of d^2=(+4-1)^2+(+16-1)^2 are d=3sqrt(26),d=-3sqrt(26)

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d^{2} = (+ 4 - 1)^{2} + (+ 16 - 1)^{2}

d = 326, d = - 326

Decimal Notation

d = 15.29705 \dots, d = - 15.29705 \dots

Solution steps

d^{2} = (4 - 1)^{2} + (16 - 1)^{2}

Simplify

(4 - 1)^{2} + (16 - 1)^{2} : 234

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

d = 234, d = - 234

234 = 326

- 234 = - 326

d = 326, d = - 326

11 m^{2} + 14 = 47

6 x^{2} = - 3 x

5 x^{2} - 7 = 3 x

z, 6 z^{2} + A z + B = 0

5 x^{2} - 2 x - 6 = - 3 x^{2} + 6 x

What are the solutions to the equation d^2=(+4-1)^2+(+16-1)^2 ?
The solutions to the equation d^2=(+4-1)^2+(+16-1)^2 are d=3sqrt(26),d=-3sqrt(26)
Find the zeros of d^2=(+4-1)^2+(+16-1)^2
The zeros of d^2=(+4-1)^2+(+16-1)^2 are d=3sqrt(26),d=-3sqrt(26)