What are the solutions to the equation -3x^2+54x=51 ?

The solutions to the equation -3x^2+54x=51 are x=1,x=17

Find the zeros of -3x^2+54x=51

The zeros of -3x^2+54x=51 are x=1,x=17

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- 3 x^{2} + 54 x = 51

x = 1, x = 17

Solution steps

- 3 x^{2} + 54 x = 51

Move

51

to the left side

- 3 x^{2} + 54 x - 51 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 54 \pm 5 4 ^{2} - 4 ( - 3 ) ( - 51 )}{2 ( - 3 )}

5 4^{2} - 4 (- 3) (- 51) = 48

x_{1, 2} = \frac{- 54 \pm 48}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- 54 + 48}{2 ( - 3 )}, x_{2} = \frac{- 54 - 48}{2 ( - 3 )}

x = \frac{- 54 + 48}{2 ( - 3 )} : 1

x = \frac{- 54 - 48}{2 ( - 3 )} : 17

The solutions to the quadratic equation are:

x = 1, x = 17

5 x + 2 x^{2} = 3

16 x^{2} + 25 x^{2} = 400

x^{2} + 2 x - 6 = 0

w^{2} + 4 w - 45 = 0

9 x^{2} - \frac{1}{4} = 0

What are the solutions to the equation -3x^2+54x=51 ?
The solutions to the equation -3x^2+54x=51 are x=1,x=17
Find the zeros of -3x^2+54x=51
The zeros of -3x^2+54x=51 are x=1,x=17