What are the solutions to the equation 5+2x^2=6x ?

The solutions to the equation 5+2x^2=6x are x= 3/2+i 1/2 ,x= 3/2-i 1/2

Find the zeros of 5+2x^2=6x

The zeros of 5+2x^2=6x are x= 3/2+i 1/2 ,x= 3/2-i 1/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

5 + 2 x^{2} = 6 x

x = \frac{3}{2} + i \frac{1}{2}, x = \frac{3}{2} - i \frac{1}{2}

Solution steps

5 + 2 x^{2} = 6 x

Move

6 x

to the left side

5 + 2 x^{2} - 6 x = 0

Write in the standard form

a x^{2} + b x + c = 0

2 x^{2} - 6 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 2 \cdot 5}{2 \cdot 2}

Simplify

(- 6)^{2} - 4 \cdot 2 \cdot 5 : 2 i

x_{1, 2} = \frac{- ( - 6 ) \pm 2 i}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 2 i}{2 \cdot 2}, x_{2} = \frac{- ( - 6 ) - 2 i}{2 \cdot 2}

x = \frac{- ( - 6 ) + 2 i}{2 \cdot 2} : \frac{3}{2} + i \frac{1}{2}

x = \frac{- ( - 6 ) - 2 i}{2 \cdot 2} : \frac{3}{2} - i \frac{1}{2}

The solutions to the quadratic equation are:

x = \frac{3}{2} + i \frac{1}{2}, x = \frac{3}{2} - i \frac{1}{2}

x (2 x - 3) = - 1

2 x^{2} - 4 x + 3 = 0

- x^{2} + 4 = 2 x^{2} - 5

42 = x^{2} + x

x^{2} + 12 x + 64 = 0

What are the solutions to the equation 5+2x^2=6x ?
The solutions to the equation 5+2x^2=6x are x= 3/2+i 1/2 ,x= 3/2-i 1/2
Find the zeros of 5+2x^2=6x
The zeros of 5+2x^2=6x are x= 3/2+i 1/2 ,x= 3/2-i 1/2