What are the solutions to the equation ((x-2)^2)/2 =x+2 ?

The solutions to the equation ((x-2)^2)/2 =x+2 are x=6,x=0

Find the zeros of ((x-2)^2)/2 =x+2

The zeros of ((x-2)^2)/2 =x+2 are x=6,x=0

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\frac{( x - 2 ) ^{2}}{2} = x + 2

x = 6, x = 0

Solution steps

\frac{( x - 2 ) ^{2}}{2} = x + 2

Multiply both sides by

2

(x - 2)^{2} = 2 x + 4

Expand

(x - 2)^{2} : x^{2} - 4 x + 4

x^{2} - 4 x + 4 = 2 x + 4

Move

4

to the left side

x^{2} - 4 x = 2 x

Move

2 x

to the left side

x^{2} - 6 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 6)^{2} - 4 \cdot 1 \cdot 0 = 6

x_{1, 2} = \frac{- ( - 6 ) \pm 6}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 6}{2 \cdot 1}, x_{2} = \frac{- ( - 6 ) - 6}{2 \cdot 1}

x = \frac{- ( - 6 ) + 6}{2 \cdot 1} : 6

x = \frac{- ( - 6 ) - 6}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

x = 6, x = 0

x^{2} - 2 x + 4 = 0

4 a^{2} + 6 = 106

0 = 8 - 9 x^{2} + 13 x

x, x^{2} - x y + 2 y = 1

3 x^{2} + 2 x + 3 = 2 x + 1

What are the solutions to the equation ((x-2)^2)/2 =x+2 ?
The solutions to the equation ((x-2)^2)/2 =x+2 are x=6,x=0
Find the zeros of ((x-2)^2)/2 =x+2
The zeros of ((x-2)^2)/2 =x+2 are x=6,x=0