What are the solutions to the equation 2x^2+7xsqrt(3)+9=0 ?

The solutions to the equation 2x^2+7xsqrt(3)+9=0 are x=-(sqrt(3))/2 ,x=-3sqrt(3)

Find the zeros of 2x^2+7xsqrt(3)+9=0

The zeros of 2x^2+7xsqrt(3)+9=0 are x=-(sqrt(3))/2 ,x=-3sqrt(3)

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2 x^{2} + 7 x 3 + 9 = 0

x = - \frac{3}{2}, x = - 33

Decimal Notation

x = - 0.86602 \dots, x = - 5.19615 \dots

Solution steps

2 x^{2} + 7 x 3 + 9 = 0

Write in the standard form

a x^{2} + b x + c = 0

2 x^{2} + 73 x + 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 3 \pm ( 7 3 ) ^{2} - 4 \cdot 2 \cdot 9}{2 \cdot 2}

(73)^{2} - 4 \cdot 2 \cdot 9 = 53

x_{1, 2} = \frac{- 7 3 \pm 5 3}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 7 3 + 5 3}{2 \cdot 2}, x_{2} = \frac{- 7 3 - 5 3}{2 \cdot 2}

x = \frac{- 7 3 + 5 3}{2 \cdot 2} : - \frac{3}{2}

x = \frac{- 7 3 - 5 3}{2 \cdot 2} : - 33

The solutions to the quadratic equation are:

x = - \frac{3}{2}, x = - 33

8 x^{2} = 7 - 10 x

2 x^{2} = \frac{1}{2}

y, 2 x^{3} + 3 y^{2} = 3 x + 7

5 8^{2} = x^{2} + x^{2}

3 x^{2} + 6 x - 5 = 0

What are the solutions to the equation 2x^2+7xsqrt(3)+9=0 ?
The solutions to the equation 2x^2+7xsqrt(3)+9=0 are x=-(sqrt(3))/2 ,x=-3sqrt(3)
Find the zeros of 2x^2+7xsqrt(3)+9=0
The zeros of 2x^2+7xsqrt(3)+9=0 are x=-(sqrt(3))/2 ,x=-3sqrt(3)