What are the solutions to the equation 3c^2+9c-7=-6 ?

The solutions to the equation 3c^2+9c-7=-6 are c=(-9+sqrt(93))/6 ,c=(-9-sqrt(93))/6

Find the zeros of 3c^2+9c-7=-6

The zeros of 3c^2+9c-7=-6 are c=(-9+sqrt(93))/6 ,c=(-9-sqrt(93))/6

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3 c^{2} + 9 c - 7 = - 6

c = \frac{- 9 + 93}{6}, c = \frac{- 9 - 93}{6}

Decimal Notation

c = 0.10727 \dots, c = - 3.10727 \dots

Solution steps

3 c^{2} + 9 c - 7 = - 6

Move

6

to the left side

3 c^{2} + 9 c - 1 = 0

Solve with the quadratic formula

c_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 3 ( - 1 )}{2 \cdot 3}

9^{2} - 4 \cdot 3 (- 1) = 93

c_{1, 2} = \frac{- 9 \pm 93}{2 \cdot 3}

Separate the solutions

c_{1} = \frac{- 9 + 93}{2 \cdot 3}, c_{2} = \frac{- 9 - 93}{2 \cdot 3}

c = \frac{- 9 + 93}{2 \cdot 3} : \frac{- 9 + 93}{6}

c = \frac{- 9 - 93}{2 \cdot 3} : \frac{- 9 - 93}{6}

The solutions to the quadratic equation are:

c = \frac{- 9 + 93}{6}, c = \frac{- 9 - 93}{6}

10 a^{2} - 3 a - 1 = 0

x^{2} - 8 x - 29 = 0

2 x^{2} - 8 x + 15

2 x^{2} - 12 x - 3 = 0

5 x + 3 x^{2} = 4 x - 7

What are the solutions to the equation 3c^2+9c-7=-6 ?
The solutions to the equation 3c^2+9c-7=-6 are c=(-9+sqrt(93))/6 ,c=(-9-sqrt(93))/6
Find the zeros of 3c^2+9c-7=-6
The zeros of 3c^2+9c-7=-6 are c=(-9+sqrt(93))/6 ,c=(-9-sqrt(93))/6