What are the solutions to the equation 4x^2+15x-105=x^2+3 ?

The solutions to the equation 4x^2+15x-105=x^2+3 are x=4,x=-9

Find the zeros of 4x^2+15x-105=x^2+3

The zeros of 4x^2+15x-105=x^2+3 are x=4,x=-9

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4 x^{2} + 15 x - 105 = x^{2} + 3

x = 4, x = - 9

Solution steps

4 x^{2} + 15 x - 105 = x^{2} + 3

Move

3

to the left side

4 x^{2} + 15 x - 108 = x^{2}

Move

x^{2}

to the left side

3 x^{2} + 15 x - 108 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 15 \pm 1 5 ^{2} - 4 \cdot 3 ( - 108 )}{2 \cdot 3}

1 5^{2} - 4 \cdot 3 (- 108) = 39

x_{1, 2} = \frac{- 15 \pm 39}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 15 + 39}{2 \cdot 3}, x_{2} = \frac{- 15 - 39}{2 \cdot 3}

x = \frac{- 15 + 39}{2 \cdot 3} : 4

x = \frac{- 15 - 39}{2 \cdot 3} : - 9

The solutions to the quadratic equation are:

x = 4, x = - 9

317 = 13 t^{2} - 268

3 x (x - 3) = 6 x^{2} - 10 x

e^{2} = - 7 e + 30

g^{2} - 9 g - 65 = 5

x^{2} + x - 30 = 0

What are the solutions to the equation 4x^2+15x-105=x^2+3 ?
The solutions to the equation 4x^2+15x-105=x^2+3 are x=4,x=-9
Find the zeros of 4x^2+15x-105=x^2+3
The zeros of 4x^2+15x-105=x^2+3 are x=4,x=-9