What are the solutions to the equation -4x^2+x=-3 ?

The solutions to the equation -4x^2+x=-3 are x=-3/4 ,x=1

Find the zeros of -4x^2+x=-3

The zeros of -4x^2+x=-3 are x=-3/4 ,x=1

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- 4 x^{2} + x = - 3

x = - \frac{3}{4}, x = 1

Decimal Notation

x = - 0.75, x = 1

Solution steps

- 4 x^{2} + x = - 3

Move

3

to the left side

- 4 x^{2} + x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 ( - 4 ) \cdot 3}{2 ( - 4 )}

1^{2} - 4 (- 4) \cdot 3 = 7

x_{1, 2} = \frac{- 1 \pm 7}{2 ( - 4 )}

Separate the solutions

x_{1} = \frac{- 1 + 7}{2 ( - 4 )}, x_{2} = \frac{- 1 - 7}{2 ( - 4 )}

x = \frac{- 1 + 7}{2 ( - 4 )} : - \frac{3}{4}

x = \frac{- 1 - 7}{2 ( - 4 )} : 1

The solutions to the quadratic equation are:

x = - \frac{3}{4}, x = 1

x^{2} - 12 x = - 6

3 (4 x + 1)^{2} - 1 = 11

4 w^{2} + 11 w + 3 = - 1

5 r^{2} = - 10 + 27 r

u^{2} + 2 u - 8 = 0

What are the solutions to the equation -4x^2+x=-3 ?
The solutions to the equation -4x^2+x=-3 are x=-3/4 ,x=1
Find the zeros of -4x^2+x=-3
The zeros of -4x^2+x=-3 are x=-3/4 ,x=1