What are the solutions to the equation 4hg^3= 1/3 h^2k ?

The solutions to the equation 4hg^3= 1/3 h^2k are h=(12g^3)/k ,h=0;\quad k\ne 0

Find the zeros of 4hg^3= 1/3 h^2k

The zeros of 4hg^3= 1/3 h^2k are h=(12g^3)/k ,h=0;\quad k\ne 0

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4 h g^{3} = \frac{1}{3} h^{2} k

h = \frac{12 g ^{3}}{k}, h = 0; k \neq = 0

Solution steps

4 h g^{3} = \frac{1}{3} h^{2} k

Multiply both sides by

3

12 g^{3} h = k h^{2}

Switch sides

k h^{2} = 12 g^{3} h

Move

12 g^{3} h

to the left side

k h^{2} - 12 g^{3} h = 0

Solve with the quadratic formula

h_{1, 2} = \frac{- ( - 12 g ^{3} ) \pm ( - 12 g ^{3} ) ^{2} - 4 k \cdot 0}{2 k}

Simplify

(- 12 g^{3})^{2} - 4 k \cdot 0 : 12 g^{3}

h_{1, 2} = \frac{- ( - 12 g ^{3} ) \pm 12 g ^{3}}{2 k}; k \neq = 0

Separate the solutions

h_{1} = \frac{- ( - 12 g ^{3} ) + 12 g ^{3}}{2 k}, h_{2} = \frac{- ( - 12 g ^{3} ) - 12 g ^{3}}{2 k}

h = \frac{- ( - 12 g ^{3} ) + 12 g ^{3}}{2 k} : \frac{12 g ^{3}}{k}

h = \frac{- ( - 12 g ^{3} ) - 12 g ^{3}}{2 k} : 0

The solutions to the quadratic equation are:

h = \frac{12 g ^{3}}{k}, h = 0; k \neq = 0

(3 x - 4)^{2} = 7

t, x = 9 t^{2}

x^{2} = (- 2) - 4

90 = (x + 8) (x + 7)

x^{2} + 4 x = - 10

What are the solutions to the equation 4hg^3= 1/3 h^2k ?
The solutions to the equation 4hg^3= 1/3 h^2k are h=(12g^3)/k ,h=0;\quad k\ne 0
Find the zeros of 4hg^3= 1/3 h^2k
The zeros of 4hg^3= 1/3 h^2k are h=(12g^3)/k ,h=0;\quad k\ne 0