What are the solutions to the equation quadraticformula 2x^2+3x=27 ?

The solutions to the equation quadraticformula 2x^2+3x=27 are x=3,x=-9/2

Find the zeros of quadraticformula 2x^2+3x=27

The zeros of quadraticformula 2x^2+3x=27 are x=3,x=-9/2

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2 x^{2} + 3 x = 27

x = 3, x = - \frac{9}{2}

Decimal Notation

x = 3, x = - 4.5

Solution steps

2 x^{2} + 3 x = 27

Move

27

to the left side

2 x^{2} + 3 x - 27 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 2 ( - 27 )}{2 \cdot 2}

3^{2} - 4 \cdot 2 (- 27) = 15

x_{1, 2} = \frac{- 3 \pm 15}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 3 + 15}{2 \cdot 2}, x_{2} = \frac{- 3 - 15}{2 \cdot 2}

x = \frac{- 3 + 15}{2 \cdot 2} : 3

x = \frac{- 3 - 15}{2 \cdot 2} : - \frac{9}{2}

The solutions to the quadratic equation are:

x = 3, x = - \frac{9}{2}

p^{2} + 6 p = - 8

N (t) = 4 t - t^{2}

(5 p + 1)^{2} = 8

w^{2} - 3 w - 4 = 0

2 a^{2} x^{2} + 3 a x - 2 = 0

What are the solutions to the equation quadraticformula 2x^2+3x=27 ?
The solutions to the equation quadraticformula 2x^2+3x=27 are x=3,x=-9/2
Find the zeros of quadraticformula 2x^2+3x=27
The zeros of quadraticformula 2x^2+3x=27 are x=3,x=-9/2