What are the solutions to the equation (k-4)^2=169 ?

The solutions to the equation (k-4)^2=169 are k=17,k=-9

Find the zeros of (k-4)^2=169

The zeros of (k-4)^2=169 are k=17,k=-9

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(k - 4)^{2} = 169

k = 17, k = - 9

Solution steps

(k - 4)^{2} = 169

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

k - 4 = 169 : k = 17

Solve

k - 4 = - 169 : k = - 9

The solutions to the quadratic equation are:

k = 17, k = - 9

x^{2} + 14 x = 32

(2 x + 5)^{2} - (2 x + 5) - 6 = 0

28.1 8^{2} = w^{2} + (4 w)^{2}

z^{2} = - 16

(26 - x)^{2} + (13 - x)^{2} = x^{2}

What are the solutions to the equation (k-4)^2=169 ?
The solutions to the equation (k-4)^2=169 are k=17,k=-9
Find the zeros of (k-4)^2=169
The zeros of (k-4)^2=169 are k=17,k=-9