What are the solutions to the equation (19x-1)^2-3(19x-1)-4=0 ?

The solutions to the equation (19x-1)^2-3(19x-1)-4=0 are x= 5/19 ,x=0

Find the zeros of (19x-1)^2-3(19x-1)-4=0

The zeros of (19x-1)^2-3(19x-1)-4=0 are x= 5/19 ,x=0

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(19 x - 1)^{2} - 3 (19 x - 1) - 4 = 0

x = \frac{5}{19}, x = 0

Decimal Notation

x = 0.26315 \dots, x = 0

Solution steps

(19 x - 1)^{2} - 3 (19 x - 1) - 4 = 0

Expand

(19 x - 1)^{2} - 3 (19 x - 1) - 4 : 361 x^{2} - 95 x

361 x^{2} - 95 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 95 ) \pm ( - 95 ) ^{2} - 4 \cdot 361 \cdot 0}{2 \cdot 361}

(- 95)^{2} - 4 \cdot 361 \cdot 0 = 95

x_{1, 2} = \frac{- ( - 95 ) \pm 95}{2 \cdot 361}

Separate the solutions

x_{1} = \frac{- ( - 95 ) + 95}{2 \cdot 361}, x_{2} = \frac{- ( - 95 ) - 95}{2 \cdot 361}

x = \frac{- ( - 95 ) + 95}{2 \cdot 361} : \frac{5}{19}

x = \frac{- ( - 95 ) - 95}{2 \cdot 361} : 0

The solutions to the quadratic equation are:

x = \frac{5}{19}, x = 0

7 x^{2} + 13 x - 5 = 0

x (2 x + 3) + 2 = x^{2} + 2 (x + 4)

11 x + 21 = 2 x^{2}

4 x^{2} - 255 = 0

4 x^{2} - 3 x = 3

What are the solutions to the equation (19x-1)^2-3(19x-1)-4=0 ?
The solutions to the equation (19x-1)^2-3(19x-1)-4=0 are x= 5/19 ,x=0
Find the zeros of (19x-1)^2-3(19x-1)-4=0
The zeros of (19x-1)^2-3(19x-1)-4=0 are x= 5/19 ,x=0