What are the solutions to the equation 2x(x-4)=9 ?

The solutions to the equation 2x(x-4)=9 are x=(4+sqrt(34))/2 ,x=(4-sqrt(34))/2

Find the zeros of 2x(x-4)=9

The zeros of 2x(x-4)=9 are x=(4+sqrt(34))/2 ,x=(4-sqrt(34))/2

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2 x (x - 4) = 9

x = \frac{4 + 34}{2}, x = \frac{4 - 34}{2}

Decimal Notation

x = 4.91547 \dots, x = - 0.91547 \dots

Solution steps

2 x (x - 4) = 9

Expand

2 x (x - 4) : 2 x^{2} - 8 x

2 x^{2} - 8 x = 9

Move

9

to the left side

2 x^{2} - 8 x - 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 2 ( - 9 )}{2 \cdot 2}

(- 8)^{2} - 4 \cdot 2 (- 9) = 234

x_{1, 2} = \frac{- ( - 8 ) \pm 2 34}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 2 34}{2 \cdot 2}, x_{2} = \frac{- ( - 8 ) - 2 34}{2 \cdot 2}

x = \frac{- ( - 8 ) + 2 34}{2 \cdot 2} : \frac{4 + 34}{2}

x = \frac{- ( - 8 ) - 2 34}{2 \cdot 2} : \frac{4 - 34}{2}

The solutions to the quadratic equation are:

x = \frac{4 + 34}{2}, x = \frac{4 - 34}{2}

215 = 22 (0.17) x + 16 (0.98) x + x^{2}

x^{2} - 10 x + 25 = 12

x^{2} - x = e

2 c^{2} - 4 c = 4

x^{2} + 4 x = 12

What are the solutions to the equation 2x(x-4)=9 ?
The solutions to the equation 2x(x-4)=9 are x=(4+sqrt(34))/2 ,x=(4-sqrt(34))/2
Find the zeros of 2x(x-4)=9
The zeros of 2x(x-4)=9 are x=(4+sqrt(34))/2 ,x=(4-sqrt(34))/2