What are the solutions to the equation 3x(4x+5)=7(4x+5) ?

The solutions to the equation 3x(4x+5)=7(4x+5) are x=-5/4 ,x= 7/3

Find the zeros of 3x(4x+5)=7(4x+5)

The zeros of 3x(4x+5)=7(4x+5) are x=-5/4 ,x= 7/3

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3 x (4 x + 5) = 7 (4 x + 5)

x = - \frac{5}{4}, x = \frac{7}{3}

Decimal Notation

x = - 1.25, x = 2.33333 \dots

Solution steps

3 x (4 x + 5) = 7 (4 x + 5)

Move

7 (4 x + 5)

to the left side

3 x (4 x + 5) - 7 (4 x + 5) = 0

Factor

3 x (4 x + 5) - 7 (4 x + 5) : (4 x + 5) (3 x - 7)

(4 x + 5) (3 x - 7) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

4 x + 5 = 0 or 3 x - 7 = 0

Solve

4 x + 5 = 0 : x = - \frac{5}{4}

Solve

3 x - 7 = 0 : x = \frac{7}{3}

The solutions to the quadratic equation are:

x = - \frac{5}{4}, x = \frac{7}{3}

w^{2} - 25 = 0

5 x^{2} - 15 x + 9 = 0

x, x^{2} + k x + 1 = 0

(4 x + 2) (x - 4) = 13 (x - 10)

x (x - 1) = e

What are the solutions to the equation 3x(4x+5)=7(4x+5) ?
The solutions to the equation 3x(4x+5)=7(4x+5) are x=-5/4 ,x= 7/3
Find the zeros of 3x(4x+5)=7(4x+5)
The zeros of 3x(4x+5)=7(4x+5) are x=-5/4 ,x= 7/3