What are the solutions to the equation 9y^2-y-8=0 ?

The solutions to the equation 9y^2-y-8=0 are y=1,y=-8/9

Find the zeros of 9y^2-y-8=0

The zeros of 9y^2-y-8=0 are y=1,y=-8/9

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9 y^{2} - y - 8 = 0

y = 1, y = - \frac{8}{9}

Decimal Notation

y = 1, y = - 0.88888 \dots

Solution steps

9 y^{2} - y - 8 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 9 ( - 8 )}{2 \cdot 9}

(- 1)^{2} - 4 \cdot 9 (- 8) = 17

y_{1, 2} = \frac{- ( - 1 ) \pm 17}{2 \cdot 9}

Separate the solutions

y_{1} = \frac{- ( - 1 ) + 17}{2 \cdot 9}, y_{2} = \frac{- ( - 1 ) - 17}{2 \cdot 9}

y = \frac{- ( - 1 ) + 17}{2 \cdot 9} : 1

y = \frac{- ( - 1 ) - 17}{2 \cdot 9} : - \frac{8}{9}

The solutions to the quadratic equation are:

y = 1, y = - \frac{8}{9}

5 x^{2} - 18 = 0

x^{2} - 13 x + 14 = 0

6 x^{2} - 19 x = 10

x^{2} + 7 x + 10 = 4

100000 = 350 x - 0.25 x^{2}

What are the solutions to the equation 9y^2-y-8=0 ?
The solutions to the equation 9y^2-y-8=0 are y=1,y=-8/9
Find the zeros of 9y^2-y-8=0
The zeros of 9y^2-y-8=0 are y=1,y=-8/9