What are the solutions to the equation -3x^2+20x+32=0 ?

The solutions to the equation -3x^2+20x+32=0 are x=-4/3 ,x=8

Find the zeros of -3x^2+20x+32=0

The zeros of -3x^2+20x+32=0 are x=-4/3 ,x=8

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- 3 x^{2} + 20 x + 32 = 0

x = - \frac{4}{3}, x = 8

Decimal Notation

x = - 1.33333 \dots, x = 8

Solution steps

- 3 x^{2} + 20 x + 32 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 ( - 3 ) \cdot 32}{2 ( - 3 )}

2 0^{2} - 4 (- 3) \cdot 32 = 28

x_{1, 2} = \frac{- 20 \pm 28}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- 20 + 28}{2 ( - 3 )}, x_{2} = \frac{- 20 - 28}{2 ( - 3 )}

x = \frac{- 20 + 28}{2 ( - 3 )} : - \frac{4}{3}

x = \frac{- 20 - 28}{2 ( - 3 )} : 8

The solutions to the quadratic equation are:

x = - \frac{4}{3}, x = 8

- 5 x^{2} + 180 = 0

20000 = x^{2} + 100 x

x, 0 = 3 x^{2} + 3 y^{2}

5 x^{2} - 1 = 4

r^{2} = 18

What are the solutions to the equation -3x^2+20x+32=0 ?
The solutions to the equation -3x^2+20x+32=0 are x=-4/3 ,x=8
Find the zeros of -3x^2+20x+32=0
The zeros of -3x^2+20x+32=0 are x=-4/3 ,x=8