What are the solutions to the equation x^2+15x-8=0 ?

The solutions to the equation x^2+15x-8=0 are x=(-15+sqrt(257))/2 ,x=(-15-sqrt(257))/2

Find the zeros of x^2+15x-8=0

The zeros of x^2+15x-8=0 are x=(-15+sqrt(257))/2 ,x=(-15-sqrt(257))/2

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x^{2} + 15 x - 8 = 0

x = \frac{- 15 + 257}{2}, x = \frac{- 15 - 257}{2}

Decimal Notation

x = 0.51560 \dots, x = - 15.51560 \dots

Solution steps

x^{2} + 15 x - 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 15 \pm 1 5 ^{2} - 4 \cdot 1 \cdot ( - 8 )}{2 \cdot 1}

1 5^{2} - 4 \cdot 1 \cdot (- 8) = 257

x_{1, 2} = \frac{- 15 \pm 257}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 15 + 257}{2 \cdot 1}, x_{2} = \frac{- 15 - 257}{2 \cdot 1}

x = \frac{- 15 + 257}{2 \cdot 1} : \frac{- 15 + 257}{2}

x = \frac{- 15 - 257}{2 \cdot 1} : \frac{- 15 - 257}{2}

The solutions to the quadratic equation are:

x = \frac{- 15 + 257}{2}, x = \frac{- 15 - 257}{2}

2 x (x - 5) + 2 = 3 x

5 x - 7 x^{2} = 7

35 x^{2} - 2 = 7 - 14 x^{2}

4 x (3 x + 2) = 24 x + 16

x^{2} - 16 x + 3 x = 90

What are the solutions to the equation x^2+15x-8=0 ?
The solutions to the equation x^2+15x-8=0 are x=(-15+sqrt(257))/2 ,x=(-15-sqrt(257))/2
Find the zeros of x^2+15x-8=0
The zeros of x^2+15x-8=0 are x=(-15+sqrt(257))/2 ,x=(-15-sqrt(257))/2