What are the solutions to the equation (x-4)^2=12 ?

The solutions to the equation (x-4)^2=12 are x=2sqrt(3)+4,x=-2sqrt(3)+4

Find the zeros of (x-4)^2=12

The zeros of (x-4)^2=12 are x=2sqrt(3)+4,x=-2sqrt(3)+4

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(x - 4)^{2} = 12

x = 23 + 4, x = - 23 + 4

Solution steps

(x - 4)^{2} = 12

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 4 = 12 : x = 23 + 4

Solve

x - 4 = - 12 : x = - 23 + 4

The solutions to the quadratic equation are:

x = 23 + 4, x = - 23 + 4

5 b + 0.2 c + 0.8 b

lo g_{4} (128)

\frac{x}{5} + \frac{x}{2} = \frac{7}{10}

6 x + 8 \geq - 4

- 13 - 7

What are the solutions to the equation (x-4)^2=12 ?
The solutions to the equation (x-4)^2=12 are x=2sqrt(3)+4,x=-2sqrt(3)+4
Find the zeros of (x-4)^2=12
The zeros of (x-4)^2=12 are x=2sqrt(3)+4,x=-2sqrt(3)+4