What are the solutions to the equation 4a^2-11a+4=0 ?

The solutions to the equation 4a^2-11a+4=0 are a=(11+sqrt(57))/8 ,a=(11-sqrt(57))/8

Find the zeros of 4a^2-11a+4=0

The zeros of 4a^2-11a+4=0 are a=(11+sqrt(57))/8 ,a=(11-sqrt(57))/8

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4 a^{2} - 11 a + 4 = 0

a = \frac{11 + 57}{8}, a = \frac{11 - 57}{8}

Decimal Notation

a = 2.31872 \dots, a = 0.43127 \dots

Solution steps

4 a^{2} - 11 a + 4 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- ( - 11 ) \pm ( - 11 ) ^{2} - 4 \cdot 4 \cdot 4}{2 \cdot 4}

(- 11)^{2} - 4 \cdot 4 \cdot 4 = 57

a_{1, 2} = \frac{- ( - 11 ) \pm 57}{2 \cdot 4}

Separate the solutions

a_{1} = \frac{- ( - 11 ) + 57}{2 \cdot 4}, a_{2} = \frac{- ( - 11 ) - 57}{2 \cdot 4}

a = \frac{- ( - 11 ) + 57}{2 \cdot 4} : \frac{11 + 57}{8}

a = \frac{- ( - 11 ) - 57}{2 \cdot 4} : \frac{11 - 57}{8}

The solutions to the quadratic equation are:

a = \frac{11 + 57}{8}, a = \frac{11 - 57}{8}

5 d^{2} - 7 d + 3 = 2

0 = x^{2} + 20 x + 3

4 x^{2} + 16 x = 48

5 n^{2} - 2 = 92

12 - 4 x + 2 x^{2} = 7

What are the solutions to the equation 4a^2-11a+4=0 ?
The solutions to the equation 4a^2-11a+4=0 are a=(11+sqrt(57))/8 ,a=(11-sqrt(57))/8
Find the zeros of 4a^2-11a+4=0
The zeros of 4a^2-11a+4=0 are a=(11+sqrt(57))/8 ,a=(11-sqrt(57))/8