What are the solutions to the equation x^2+sqrt(2)x-1=0 ?

The solutions to the equation x^2+sqrt(2)x-1=0 are x=(-sqrt(2)+sqrt(6))/2 ,x=(-sqrt(2)-sqrt(6))/2

Find the zeros of x^2+sqrt(2)x-1=0

The zeros of x^2+sqrt(2)x-1=0 are x=(-sqrt(2)+sqrt(6))/2 ,x=(-sqrt(2)-sqrt(6))/2

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x^{2} + 2 x - 1 = 0

x = \frac{- 2 + 6}{2}, x = \frac{- 2 - 6}{2}

Decimal Notation

x = 0.51763 \dots, x = - 1.93185 \dots

Solution steps

x^{2} + 2 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm ( 2 ) ^{2} - 4 \cdot 1 \cdot ( - 1 )}{2 \cdot 1}

(2)^{2} - 4 \cdot 1 \cdot (- 1) = 6

x_{1, 2} = \frac{- 2 \pm 6}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 2 + 6}{2 \cdot 1}, x_{2} = \frac{- 2 - 6}{2 \cdot 1}

x = \frac{- 2 + 6}{2 \cdot 1} : \frac{- 2 + 6}{2}

x = \frac{- 2 - 6}{2 \cdot 1} : \frac{- 2 - 6}{2}

The solutions to the quadratic equation are:

x = \frac{- 2 + 6}{2}, x = \frac{- 2 - 6}{2}

- 4 x^{2} + 12 x - 11 = 0

40 (p^{2} - 1) = 39 p

4 x^{2} - 23 x + 13 = - 3 x + 4

5 z^{2} - 21 z + 11 = - 4 z

2 x^{2} + 11 x - 63 = 0

What are the solutions to the equation x^2+sqrt(2)x-1=0 ?
The solutions to the equation x^2+sqrt(2)x-1=0 are x=(-sqrt(2)+sqrt(6))/2 ,x=(-sqrt(2)-sqrt(6))/2
Find the zeros of x^2+sqrt(2)x-1=0
The zeros of x^2+sqrt(2)x-1=0 are x=(-sqrt(2)+sqrt(6))/2 ,x=(-sqrt(2)-sqrt(6))/2