What are the solutions to the equation -2x^2-4x-3=0 ?

The solutions to the equation -2x^2-4x-3=0 are x=-1-i(sqrt(2))/2 ,x=-1+i(sqrt(2))/2

Find the zeros of -2x^2-4x-3=0

The zeros of -2x^2-4x-3=0 are x=-1-i(sqrt(2))/2 ,x=-1+i(sqrt(2))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

- 2 x^{2} - 4 x - 3 = 0

x = - 1 - i \frac{2}{2}, x = - 1 + i \frac{2}{2}

Solution steps

- 2 x^{2} - 4 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 ( - 2 ) ( - 3 )}{2 ( - 2 )}

Simplify

(- 4)^{2} - 4 (- 2) (- 3) : 22 i

x_{1, 2} = \frac{- ( - 4 ) \pm 2 2 i}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 2 2 i}{2 ( - 2 )}, x_{2} = \frac{- ( - 4 ) - 2 2 i}{2 ( - 2 )}

x = \frac{- ( - 4 ) + 2 2 i}{2 ( - 2 )} : - 1 - i \frac{2}{2}

x = \frac{- ( - 4 ) - 2 2 i}{2 ( - 2 )} : - 1 + i \frac{2}{2}

The solutions to the quadratic equation are:

x = - 1 - i \frac{2}{2}, x = - 1 + i \frac{2}{2}

(x + 2)^{2} - 5 = 31

r (r^{1} + r^{2}) = r^{1} r^{2}

x^{2} = - 4 b

0 = 4 x^{2} - 9

t^{2} - 64 = 0

What are the solutions to the equation -2x^2-4x-3=0 ?
The solutions to the equation -2x^2-4x-3=0 are x=-1-i(sqrt(2))/2 ,x=-1+i(sqrt(2))/2
Find the zeros of -2x^2-4x-3=0
The zeros of -2x^2-4x-3=0 are x=-1-i(sqrt(2))/2 ,x=-1+i(sqrt(2))/2